[UT] inStr(), Mid(), Left(), Right() question...

[Qjahe]

Hi,

i've been trying to understand those above little string functions.

InStr Wiki description:

int InStr (coerce string S, coerce string t) [static]
If the string t is found inside S InStr returns the starting position with the first character of S being 0. If t is not found InStr returns -1.

I have the following string:
myString = "CONNECT MYIP LOGIN PWD PORT"

now InStr returns the POSITION of the first character found in the string. in this example it would be returning 7 if I had:

 i = InStr(myString," ");

I have the loc of my first space.. I can get CONNECT alone by using:

tmpString = Left(myString, i)

my Question is how do I get the rest seperately? how can I make inStr move to the next character(space) ?

anyone able to explain this to me?

Thanks

Qjahe

 

[Silver5123]

I presume you want to cut out each section of the string to different strings/variables? So...

Well, like you have:

myString = "CONNECT MYIP LOGIN PWD PORT";

i = InStr(myString, " ") 
//i = 7;

tmpString = Left(myString, i); 
//tmpString is the leftmost 7 characters "CONNECT"

myString = Right(myString, Len(myString) - i - 1)
//myString is now equal to the 19 right most characters (27 - 7 - 1) "MYIP LOGIN PWD PORT"

i = InStr(myString, " ");  
//i = 4

myIPString = Left(myString, i); 
//myIPString is the 4 left most characters "MYIP"

Then just keep doing the same thing for LOGIN PWD and PORT.

 

[Qjahe]

BreakEmUp()

I came up with this little function to Break a String up...

function BreakEmUp(string Text, string C){
  local int i, j;
  local string BEU[20];
  j=0;
  while(i != -1){
    i = inStr(Text,C);
    if(i != -1){
      BEU[j] = Left(Text,i);
      Text = Mid(Text,i+1)
      j++;
    }
  }
  return BEU;
}

function someOtherFunction(){
  local string B[20];
  B = BreakEmUp(Text," ");
}

When I try to compile it, it gives me the following error
Error, Bad or missing expression in '='

At the exact line where I am calling my function BreakEmUp... I can't return a whole Array in UScript? What am I doing wrong?

Thanks guys.

Qjahe

 

[Wormbo]

myString = Right(myString, Len(myString) - i - 1)

This could be better done with

myString = Mid(myString, i+1);

Same effect, mut much less code and it's easier to understand what it does. (take all characters, beginning with the i+1st characters)

Qjahe: Your function needs a return value. (See UnrealWiki: Function Syntax)

 

[Silver5123]

Hehe...You didn't declare BreakEmUp to return anything.

Try:

function String[] BreakEmUp(string Text, string C)

 

[Wormbo]

Static arrays can't be used as the return value of a function. In UT2003 I'd have recommended using a dynamic array, but in UT you're screwed.

Maybe you should use an out parameter like this:

function BreakEmUp(string Text, string C, out string Parts[20]) {
...
}

 

[Qjahe]

Error, Declaration: Missing string size

when I declare it like this:

function String[] BreakEmUp(string Text, string C){

I get the error "Error, Declaration: Missing string size"...
when I decalre it like this:

function String[20] BreakEmUp(string Text, string C){

I get the warning:
"Warning, String sizes are now obsolete; all strings are dynamically sized"
at the Function declaration line...

and the following as error:
"Error, Array mismatch in '=' "
at the line where I call the function...

any ideas...

Thanks guys

 

[Silver5123]

Sorry, I was thinking of Java.


Wormbo has it right, you have to have an out string in the parameters.

 

[Qjahe]

yeah sorry I saw the answer after the post.

I'm still getting errors.
with the out parameter in the declaration how am I supposed to call it?

function someOtherFunction(){
  local string B[20];
  B = BreakEmUp(Text," ",B);
}

Thanks agian guys

Qj

 

[Qjahe]

Works

Alright it works now.
if anyone wants to use it here is what I have:

function BreakEmUp(string Text, string C, out string BEU[20]) {
  local int i, j;
  j=0;
  while(i != -1){
    i = inStr(Text,C);
    if(i != -1){
      BEU[j] = Left(Text,i);
      Text = Mid(Text,i+1)
      j++;
    }
    else{
      BEU[j] = Text;
    }
  }
  return;
}

function someOtherFunction(){
  local string B[20];
  BreakEmUp(Text," ",B);
}

the array of Strings B will now contain all the words in the string splitted at the Space character. Hope it helps anyone that was searching for a split Function in [UT]

Thanks again guys
Qj